f(g(x))=6(2x^2-5x+7)

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Solution for f(g(x))=6(2x^2-5x+7) equation:


Simplifying
f(g(x)) = 6(2x2 + -5x + 7)

Multiply g * x
f(gx) = 6(2x2 + -5x + 7)

Multiply f * gx
fgx = 6(2x2 + -5x + 7)

Reorder the terms:
fgx = 6(7 + -5x + 2x2)
fgx = (7 * 6 + -5x * 6 + 2x2 * 6)
fgx = (42 + -30x + 12x2)

Solving
fgx = 42 + -30x + 12x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'gx'.
f = 42g-1x-1 + -30g-1 + 12g-1x

Simplifying
f = 42g-1x-1 + -30g-1 + 12g-1x

Reorder the terms:
f = -30g-1 + 42g-1x-1 + 12g-1x

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